how many moles of sucrose C12H22O11 does 300mL of a 0.10 M sucrose solution contain?
114
To answer this question, we need to use the relationship between molarity, volume, and number of moles. The equation for this relationship is:
Molarity (M) = Moles of solute / Volume of solution in liters
First, we need to convert the given volume from milliliters (mL) to liters (L):
300 mL = 300/1000 = 0.3 L
Next, rearranging the equation to solve for moles of solute:
Moles of solute = Molarity x Volume of solution in liters
Substituting the given values into the equation:
Moles of sucrose = 0.10 mol/L x 0.3 L
Calculating this expression:
Moles of sucrose = 0.03 moles
Therefore, 300 mL of a 0.10 M sucrose solution contains 0.03 moles of sucrose.