Posted by Elena on Thursday, April 28, 2011 at 1:40pm.
I suppose you are trying to find the integral:
I=∫2e^(2sqrt(y))/sqrt(y) dy
Use substitution
u=2sqrt(y)
du = dy/sqrt(y)
du = dy/sqrt(y)
I=∫2e^udu
=2e^u + C
=2e^(2sqrt(y)) + C
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