Posted by Ben on Wednesday, April 27, 2011 at 10:39pm.
q = Ccal x delta T
Ccal = 10,000/2.15 = 4651.2 J/K
q = [mass H2O x specific heat H2O x delta T] + [Ccal*delta T]
q = [150 x 4.184 x (33.13-22.00)] + [4651.2*(33.13-22.00)] = ??
I didn't watch my significant figures in the above. You need to take care of that after your calculation.
In #1, the heat capacity is the heat generated/degree rise in T.
In #2, the ethane burns and the water inside the calorimeter tells you how much heat is generated BECAUSE the T of the water is raised. We know the mass of the water, we know the specific heat water, and the rise in T was measured; therefore we can calculate the amount of heat generated. The heat raised the T of BOTH the water AND the calorimeter. So the total Q from burning ethane is just q from the water + q from the calorimeter.
a 225.0 gram sample of aluminum is heated and the temperature increased from 50.0 celsius to 65.0 celsius for temperature change of 15.0celsius. how many calories of heat was absorbed to produce this temperature?
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