Initially, there are 33 moles of A and 0 moles of B. How many moles of A and B will be present after the system reaches equilibrium?

a) 33 moles A; 0 moles B
b) 0 moles A; 33 moles B
c) 3 moles A; 30 moles B
d) equal amounts of A and B

The answer is given as "C" but I don't know how it was obtained :/

No K? no reaction?

Oops, here it is.

refer to the following equilibrium below:
A <===> B Keq = 10

oops, wrong thread. but i have the same question regardless.

These problems can be tough enough when we have enough information but omitting it makes it really tough. :-).

..............A ===> B
initial......33......0
change........-x.....+x
equil........33-x......x

K = 10 = (B)/(A)
10 = (x)/(33-x)
Solve for x and 33-x.
I get x = 30 = B and 33-x = 3 = A.

To determine the moles of A and B that will be present at equilibrium, we need to understand the reaction and calculate the stoichiometry. However, you have not provided any information about the reaction or its equation. This information is crucial to determine the correct answer.

If you can provide the balanced equation for the reaction, I can help you calculate the moles of A and B at equilibrium.