Math
posted by Erik on .
I cant figure this question out. I could use some help.
Solve for x
lnxlnx^2+ln5 = 0
Simplify the answer

Use the law of logarithms:
ln(a)+ln(b)=ln(ab)
ln(a)ln(b)=ln(a/b)
kln(a)= ln(a^{k})
ln(1)=0
ln(1/x)=ln(x)
so
ln(x)ln(x²)+ln(5)=0
ln(x/x²)+ln(5)=0
ln(1/x)+ln(5)=0
ln(x)+ln(5)=0
ln(x)=ln(5)
e^(ln(x))=e^(ln(5))
x=5