Posted by Erik on Wednesday, April 27, 2011 at 3:04pm.
Use the law of logarithms:
ln(a)+ln(b)=ln(ab)
ln(a)-ln(b)=ln(a/b)
kln(a)= ln(ak)
ln(1)=0
ln(1/x)=-ln(x)
so
ln(x)-ln(x²)+ln(5)=0
ln(x/x²)+ln(5)=0
ln(1/x)+ln(5)=0
-ln(x)+ln(5)=0
ln(x)=ln(5)
e^(ln(x))=e^(ln(5))
x=5
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