what volume of distilled water must be added to 165mls of stock solution to make 1200mls of diluted solution
Difference in volume
= 1200-165 ml
= 1035 ml
So 1035 ml. of distilled water must be added.
To calculate the volume of distilled water needed to make a diluted solution, we can use the formula:
V1 × C1 = V2 × C2
Where:
V1 = volume of the first solution (stock solution)
C1 = concentration of the first solution
V2 = volume of the final solution (diluted solution)
C2 = concentration of the final solution (usually desired concentration)
In this case, we are given:
V1 = 165 mL (stock solution)
V2 = 1200 mL (final solution)
C1 = concentration of the stock solution (not provided)
C2 = concentration of the final solution (not provided)
Since the concentrations are not given, we can assume that the concentration is the same before and after dilution (this assumption is usually made in dilution calculations).
Let's assume the concentration of the stock solution is x mol/L, and the concentration of the final solution is also x mol/L.
Using the formula, we can set up the equation as follows:
165 mL × x mol/L = 1200 mL × x mol/L
The x mol/L cancels out, and we can solve for x:
165 mL = 1200 mL
Simplifying, we get:
x = (1200 mL) / (165 mL)
x ≈ 7.273 mol/L
Now we know that the concentration of both the stock solution and the final solution is approximately 7.273 mol/L.
To calculate the volume of distilled water required, we subtract the volume of the stock solution from the volume of the final solution:
V_water = V2 - V1
V_water = 1200 mL - 165 mL
V_water = 1035 mL
Therefore, you would need to add approximately 1035 mL of distilled water to 165 mL of the stock solution to make 1200 mL of the diluted solution.