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December 18, 2014

December 18, 2014

Posted by **Ella** on Wednesday, April 27, 2011 at 6:37am.

- algebra -
**drwls**, Wednesday, April 27, 2011 at 6:44amLet a be the larger number.

a - b = 3

a*b = 2(a + b)

a*(a-3) = 2a + 2(a-3)

a^2 -3a = 2a + 2a -6

a^2 -7a +6 = 0

(a - 6)(a -1) = 0

a = 6 or 1

Forget the a = 1 solution, because b cannot be negative

a = 6 and b = 3

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