Wednesday

October 22, 2014

October 22, 2014

Posted by **Stacy** on Tuesday, April 26, 2011 at 10:44pm.

- Grade 11 Math -
**MathMate**, Tuesday, April 26, 2011 at 11:30pmLet x be the shorter side.

Longer side = (54-3x)/2 = 27-1.5x

Area, A = x(27-1.5x)=27x-1.5x²

To get maximum area, diff. w.r.t. x and equate to zero.

dA/dx = 27-3x=0

x=9m

longer side = 27-9*1.5=13.5m

The dog run is 9m by 13.5 m total

Total area= 121.5 m²

**Answer this Question**

**Related Questions**

Math - A rectangular study area is to be enclosed by a fence and divided into ...

math - A rectangular field is to be enclosed by a fence. Two fences parallel to ...

calculus (optimization) - a rectangular study area is to be enclosed by a fence ...

Calculus 1 - A rectangular field is enclosed by a fence and seperated into two ...

precalculus - A rectangular field is to be enclosed by a fence and divided into...

Math - A farmer uses 1034 meters of fencing to enclose a rectangular region and ...

shortest fence - this is my last question from applications of derivatives! A ...

math - i am having serious optimization problems. i don't get it!!! plz help. a ...

Math - A farmer wishes to put a fence around a rectangular field and then divide...

college Algebra - A rectangular fence is to be built along a river using the ...