Tuesday
March 31, 2015

Homework Help: Chemistry

Posted by Anonymous on Tuesday, April 26, 2011 at 7:57pm.

Barium sulfate forms as a precipitate in the following reaction:
Ba(NO3)2 (aq) + Na2SO4 (aq) -> BaSO4 (s) + 2NaNo3 (aq)
When 35.0g of Ba(nO3)s is reacted with excess Na2SO4, 29.8g of BaSO4 is recovered by the chemist.

a) Calculate the theoretical yield of BaSO4.
b) Calculate the percentage yield of BaSO4.

note: I'm not sure what I do because two of the grams -35.0g and 29.8g - are confusing me. I tried finding the molar mass. Now what?

The answer for
a) 31.3g
b) 95.2%

But I don't understand how to get it. Please explain, thank you.

Answer this Question

First Name:
School Subject:
Answer:

Related Questions

Chemistry - Barium sulfate, BaSO4 is made by the following reaction. Ba(NO3)2(aq...
Chemistry - A limiting reactants problem. 6.32g of sodium sulfate is reacted ...
Chemistry - What volume (in mL) of 0.45 M Na2SO4 solution is needed to ...
chemistry - What type of chemical rxn is Na2SO4(aq) +Ba(NO3)2(aq) the product is...
AP Chem - A chemist added an excess of sodium sulfate to a solution of a soluble...
Chemistry - !00.0 grams of Na2SO4 reacts with 150.00 grams of Ba(NO3)2to form ...
chem - what is the percent yield of the reaction between 5.2 mL of 0.1233 M ...
Chem. - in the equation Ba(NO3)2(aq)+Na2SO4 (aq) →BaSO4(s) + Na2(NO3)2...
chemistry - a 1.009g mixture of the solid salts Na2SO4 and forms an aqueous ...
Chemistry - Pb(NO3)2(aq) 2 x 10-3 M Na2SO4(aq) 2 x 10-3 M Pb(NO3)2(aq) + NaSO4(...

Members