Posted by **Nancy** on Tuesday, April 26, 2011 at 7:26pm.

A coin jar contains nickels, dimes and quarters. There are 46 coins in all. There are 11 more nickels than quarters. The value of the dimes is $1.00 less than the value of the quarters. How many coins of each type are in the jar?

- College Algebra -
**Mgraph**, Tuesday, April 26, 2011 at 8:04pm
Solve the system:

n+d+q=46

n=q+11

10d=25q-100

From the 3rd -->d=2.5q-10

The 1st: (q+11)+(2.5q-10)+q=46

q=10

n=21

d=15

- College Algebra -
**Nancy**, Tuesday, April 26, 2011 at 8:17pm
solving using the elimination method and identify the system as consistent, inconsistent or dependent.

3x-4y=8

6x-2y=10

- College Algebra -
**Anonymous**, Monday, September 3, 2012 at 9:30pm
Suppose that Maria has 120 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 14 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?

- College Algebra -
**Anonymous**, Tuesday, September 4, 2012 at 2:29pm
p+n+d=120

n=2p-14

d=3p-22

p+(2p-14)+(3p-22)=120

6p-36=120

6p=156

p=26

n=2(26)-14

n=52-14

n=38

d=3(26)-22

d=78-22

d=56

- College Algebra -
**Anonymous**, Friday, March 15, 2013 at 2:30pm
P(1, 2); Q(8, 26)

- College Algebra -
**fahengy**, Sunday, February 9, 2014 at 9:58pm
5+6

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