Posted by Nancy on Tuesday, April 26, 2011 at 7:26pm.
A coin jar contains nickels, dimes and quarters. There are 46 coins in all. There are 11 more nickels than quarters. The value of the dimes is $1.00 less than the value of the quarters. How many coins of each type are in the jar?

College Algebra  Mgraph, Tuesday, April 26, 2011 at 8:04pm
Solve the system:
n+d+q=46
n=q+11
10d=25q100
From the 3rd >d=2.5q10
The 1st: (q+11)+(2.5q10)+q=46
q=10
n=21
d=15

College Algebra  Nancy, Tuesday, April 26, 2011 at 8:17pm
solving using the elimination method and identify the system as consistent, inconsistent or dependent.
3x4y=8
6x2y=10

College Algebra  Anonymous, Monday, September 3, 2012 at 9:30pm
Suppose that Maria has 120 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 14 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?

College Algebra  Anonymous, Tuesday, September 4, 2012 at 2:29pm
p+n+d=120
n=2p14
d=3p22
p+(2p14)+(3p22)=120
6p36=120
6p=156
p=26
n=2(26)14
n=5214
n=38
d=3(26)22
d=7822
d=56

College Algebra  Anonymous, Friday, March 15, 2013 at 2:30pm
P(1, 2); Q(8, 26)

College Algebra  fahengy, Sunday, February 9, 2014 at 9:58pm
5+6
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