posted by Nancy on .
A coin jar contains nickels, dimes and quarters. There are 46 coins in all. There are 11 more nickels than quarters. The value of the dimes is $1.00 less than the value of the quarters. How many coins of each type are in the jar?
Solve the system:
From the 3rd -->d=2.5q-10
The 1st: (q+11)+(2.5q-10)+q=46
solving using the elimination method and identify the system as consistent, inconsistent or dependent.
Suppose that Maria has 120 coins consisting of pennies, nickels, and dimes. The number of nickels she has is 14 less than twice the number of pennies; the number of dimes she has is 22 less than three times the number of pennies. How many coins of each kind does she have?
P(1, 2); Q(8, 26)