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April 24, 2014

April 24, 2014

Posted by **Ashley** on Tuesday, April 26, 2011 at 5:55pm.

- precalc -
**MathMate**, Wednesday, April 27, 2011 at 9:29amNote:

we*solve*an equation for an unknown, and we*simplify*an expression.

Simplify:

log_{5}√125

=log_{5}√(5³)

= 3

(125 = 5³, so log_{5}125=3, just like log_{10}10³=3)

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