Posted by **Anonymous** on Tuesday, April 26, 2011 at 2:54pm.

how do i solve this completing the square problem: 3x^2+12x+10=0

- trig -
**MathMate**, Tuesday, April 26, 2011 at 3:31pm
3x^2+12x+10=0

3(x^2+4x+10/3)=0

(x+2)²-4+10/3=0

(x+2)²-(√(2/3))²=0

(x+2+√(2/3))(x+2-√(2/3))=0

therefore

x=-2-√(2/3) or -2+√(2/3)

- trig -
**bobpursley**, Tuesday, April 26, 2011 at 3:34pm
divide by 3

x^2+4x+10/3=0

x^2+4x + ???= -10/3 + ???

well, look at the second term. take one half of it, and square it, add to both sides.

x^2+4x+4=-10/3+4= 10/3+12/3

(x+2)^2= 2/3

take the square root of each side.

x+2= +-sqrt 2/3

x=-2+-sqrt 2/3

check that.

## Answer This Question

## Related Questions

- Algebra 1 - I have to get this last problem done it's for my project here's the ...
- alg2/trig - 1)3x^2-12x-21 solve by completing the square in simplest radical ...
- Algebra 2 - Solve by completing the square. a² - 2√(3a) + 2 = 0 Solve for ...
- Algebra - solve the equation by completing the square 3x^2-12x+1=0
- Math (Quadratics) - 3. Solve for x in 8x^2 + 2x - 4 = 0 I have tried factoring...
- COLLEGE ALGEBRA ..HELP! - Solve by completing the square 12x^2+11x=5
- COLLEGE ALGEBRA - Solve by completing the square 12x^2+11x=5
- math,correction - Is this correct now. Problem #1 solve by completing the square...
- algebra/trig - x^2+2x-15=0 solve by completing the square
- Algebra - My homework is to solve by completing the square. But how can you ...

More Related Questions