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May 28, 2015

Posted by **Diana** on Tuesday, April 26, 2011 at 8:05am.

How many solutions are there such that x and y are positive integer? (note the date 4/11/2011)

- Math -
**drwls**, Tuesday, April 26, 2011 at 9:26amThere are 182 integer values of y that make 11 y between 0 and 2002

The remainder values of 4x are:

2011, 2000, 1989, 1978, 1967, 1956, 1945, 1934, 1923, 1912... . Those 4x values resulting in an integer for x are 2000 (for y = 1), 1956 (for y = 5), 1912 (for y = 9), ... and 20 for y = 181. There are 46 such values, and therefore 46 combinations.

(x,y)

______

(500,1)

(489,5)

(478,9)

......

(5,181)

- Math -
**Diana**, Wednesday, April 27, 2011 at 8:03amnice explanation, i understand