Posted by mie on Tuesday, April 26, 2011 at 2:16am.
pH = pKa + log (base)/(acid)
5.30 = 4.699 + log(b/a)
b/a = 3.99 for one equation.
Second equation is
mLbase x 0.5M = mLacid x 0.5M
The 0.5M divides out. Substitute base 3.99*acid in the above and
mLbase =3.99(300-mLbase)
solve for mL base and subtract from 300 to obtain mL acid. You should get something close to 120 and 31 but those aren't exact.
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