a sidewalk is built 10 bricks wide by laying each brick side by side. How many inches wide is the sidewalk if each brick measure 3 5/8 inches wide?

(3 5/8) * 10

(29/8) * 10/1 = 290/8 = 36.25 = 36 1/4 in.

6x2 3/8

To find the width of the sidewalk in inches, we need to calculate the total width of the bricks and convert it to inches.

First, let's determine the total width of the bricks in inches. Each brick measures 3 5/8 inches wide.

Width of one brick = 3 5/8 inches

Next, we need to calculate the total width of all the bricks by multiplying the width of one brick by the number of bricks in a row. The sidewalk is built 10 bricks wide.

Total width of the bricks = Width of one brick × Number of bricks

Total width of the bricks = (3 5/8 inches) × 10

Now, let's calculate the total width of the bricks:
Total width of the bricks = (3 5/8 inches) × 10
Total width of the bricks = (37/8 inches) × 10
Total width of the bricks = 37/8 × 10/1
Total width of the bricks = 370/8
Total width of the bricks = 46 1/4 inches

Therefore, the sidewalk is 46 1/4 inches wide.

To find the width of the sidewalk in inches, we can multiply the number of bricks by the width of each brick.

First, let's convert the mixed number 3 5/8 to an improper fraction. To do this, we multiply the whole number (3) by the denominator (8) and add the numerator (5), then write it over the denominator:

3 * 8 = 24
24 + 5 = 29

So, 3 5/8 can be written as the improper fraction 29/8.

Now, let's calculate the width of the sidewalk. Since the sidewalk is built with 10 bricks, we multiply the width of each brick (29/8 inches) by the number of bricks (10):

(29/8) * 10 = 290/8 = 36 1/4 inches

Therefore, the sidewalk is 36 1/4 inches wide.