Saturday

October 25, 2014

October 25, 2014

Posted by **sonia** on Monday, April 25, 2011 at 2:16pm.

- pre-cal -
**MathGuru**, Monday, April 25, 2011 at 7:03pmI'm assuming your equation is this:

y = -1/2x^2 + 10x - 46

The above equation would then be in the format:

y = ax^2 + bx + c

...where a, b, and c are the coefficients of each term in this format.

Therefore, in your equation, a = -1/2, b = 10, and c = -46

To find the vertex, use this:

-b/2a for x

(4ac - b^2)/4a for y

You can also find y by substituting the value for x into the equation and solving for y.

Vertex will be in the format (x,y).

I'll let you take it from here.

**Answer this Question**

**Related Questions**

Pre Cal - write the equations of the parabola, the directrix, and the axis of ...

algebra - 6. Find the equation of each parabola described below. a) parabola ...

Pre Cal Check - focus: (0,p) vertex: if not given, then it is assumed (0,0) ...

Pre-cal - Sketech the graph of the equation y^2+4y+2x+10=0. Identify the vertex...

maths - Given that the equation of the parabola is 5y^2 + 24x = 0. Find (1)The ...

Math - Find the vertex, focus, and directrix of the parabola. x^2 - 2x + 8y + 9...

pre cal - What is the center of the conic whose equation is x^2 + 2y^2 - 6x + ...

pre cal - find the standard form of the equation of a parabola with the vertex (...

Math - Find the vertex, focus and directrix of the parabola. 4x - y^2 - 2y - 33...

Math - Find the vertex, focus, and directrix of the parabola. x^2 - 2x + 8y + 9...