Posted by **mona** on Monday, April 25, 2011 at 1:45pm.

Suppose a random sample of 36 is selected from a population with a standard deviation of 12. If the sample mean is 98, the 99% confidence interval to estimate the population mean is

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**MathGuru**, Monday, April 25, 2011 at 6:39pm
CI99 = mean + or - 2.58(sd/√n)

...where + or - 2.58 represents the 99% confidence interval using a z-table, sd = standard deviation, √ = square root, and n = sample size.

Substitute what you know into the above formula and go from there.

I hope this will help get you started.

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