Posted by Molly on Monday, April 25, 2011 at 11:04am.
The way you do this problem is to calculate Q and compare with K. Here is a good site.
http://www.ausetute.com.au/qquotient.html
So basically for the first 3 answers (Part (A)(B)(C)):
(A)and(B) - the concentrations would be equal since the mole ratio is equal and Q = K at equilibrium.
(C) - the rate of both reactions would be equal also, as Q = k, right?
(D)(1) - If the volume is increased at constant temperature their will be a !@#$%^& to the right, if i am correct, because as the pressure decreases due to the increase in volume the shift will be towards the side which contains the most moles of gas. Thus the number of moles of PCl5 would decrease.
(2) - I am sort of confused for number 2, but I predict the Kp value would increase since the pressure of PCl5 decreases and it is causing the denominator of Kp equation (Kp = Kp(prod)/Kp(react)) to decrease.
So, I was wondering if I am thinking this clearly and if I am on the right path?
!@#$%^& = "shift", I made a spelling mistake.
!@#$%^&
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