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April 16, 2014

April 16, 2014

Posted by **Hannah** on Monday, April 25, 2011 at 4:42am.

- College math/bus calc -
**Damon**, Monday, April 25, 2011 at 5:05amx = length

y = width

A = x y

P = 60 = x + 2 y

so

x = 60 - 2 y

A = (60 - 2 y) y = 60 y - 2 y^2

2 y^2 - 60 y = -A

y^2 - 30 y = -A/2

complete square for vertex of parabola

y^2 - 30 y + 225 = -A/2 + 225

(y-15)^2 = -A/2 + 225 = -(1/2)(A-450)

so y = 15 at vertex

A = 450 at vertex

so

15 by 30 for 450 ft^2 area

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