Posted by Jacob on .
Sam invested $1950 part of it at 6% and the rest at 8% yearly interest. The yearly income on the 8% invest was 6$ more then twice the income from the 6% investment. how much did he invest at each rate

Algebra 
bobpursley,
let S be the amount at six percent, E be the amount at Eight percent.
S+E=1950
.06S=2*.08E+6
can you handle if from here? 
Algebra 
Jacob,
Not really having trouble with this one for some reason

Algebra 
bobpursley,
well, s=1950E
so
.06(1950E)=2(.08E)+6
now solve for E.
then to get S,subtract E from 1950