Posted by **Jacob** on Sunday, April 24, 2011 at 7:27pm.

Sam invested $1950 part of it at 6% and the rest at 8% yearly interest. The yearly income on the 8% invest was 6$ more then twice the income from the 6% investment. how much did he invest at each rate

- Algebra -
**bobpursley**, Sunday, April 24, 2011 at 7:43pm
let S be the amount at six percent, E be the amount at Eight percent.

S+E=1950

.06S=2*.08E+6

can you handle if from here?

- Algebra -
**Jacob**, Sunday, April 24, 2011 at 8:03pm
Not really having trouble with this one for some reason

- Algebra -
**bobpursley**, Sunday, April 24, 2011 at 8:31pm
well, s=1950-E

so

.06(1950-E)=2(.08E)+6

now solve for E.

then to get S,subtract E from 1950

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