Posted by Jacob on Sunday, April 24, 2011 at 7:27pm.
Sam invested $1950 part of it at 6% and the rest at 8% yearly interest. The yearly income on the 8% invest was 6$ more then twice the income from the 6% investment. how much did he invest at each rate

Algebra  bobpursley, Sunday, April 24, 2011 at 7:43pm
let S be the amount at six percent, E be the amount at Eight percent.
S+E=1950
.06S=2*.08E+6
can you handle if from here?

Algebra  Jacob, Sunday, April 24, 2011 at 8:03pm
Not really having trouble with this one for some reason

Algebra  bobpursley, Sunday, April 24, 2011 at 8:31pm
well, s=1950E
so
.06(1950E)=2(.08E)+6
now solve for E.
then to get S,subtract E from 1950
Answer This Question
Related Questions
 algebra  Sam invested $2150, part of it at 6% and the rest at 8% yearly ...
 algebra  Could you please answer this? Investment. Part of $25,000 is invested ...
 algebra  Melinda invested three times as much money at 9% yearly interest as ...
 algebra  Part $30000 is invested at 6% another part at 7% and the remainder at ...
 algebra 2  Lisa Chen invested $24,000, part at 8% and the rest at 7.2%. How ...
 algebra 2  Lisa Chen invested $24,000, part at 8% and the rest at 7.2%. How ...
 algebra 2  Lisa Chen invested $24,000, part at 8% and the rest at 7.2%. How ...
 Algebra 2 URGENT  Lina Chen invested $24,000, part at 8% and the rest at 7.2%. ...
 math  1. Investment. Part of $25,000 is invested at 10 percent, another part is...
 math  Mr Jacob has twice as much money invested at 5% simple annual interest as...
More Related Questions