Posted by Deanna on Sunday, April 24, 2011 at 5:05pm.
I got it P1/T1=P2/T2 will get you there
initial pressure of the air(P1) = 762mm Hg
P2 = ?
T1 = 25.7+273 = 298.7K
T2 = 38.8+273 = 311.8K
P2 =?
P2 = 762 mm Hg x 311.8K/298.7K = 795.42 mm Hg
so, pressure of ethanol = 980 - 795.42 = 184.58 mm Hg
Answer in three sig fig will be 184 mm Hg.
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