Posted by Ginny on Sunday, April 24, 2011 at 4:40pm.
1. P(1,2), Q(25,2), R(10,20).
X = (1+25+10) / 3 = 12.
Y = (2+2+20) / 3 = 8.
C(12,8). = Coordinates of Centroid.
2. SIDE PQ:
Xo = (1+25) / 2 = 13.
Yo = (2+2) / 2 = 2.
M(13,2).
m = (2-2) / (25-1) = 0/24 = 0.
m2 = -1/0 = Undefined = slope of perpendicular bisector(P.B.).
Eq1: X = 13 = Eq of P.B. of PQ = a ver line.
SIDE PR:
Xo = (1+10) / 2 = 5.5.
Yo = (2+20) / 2 = 11.
M(5.5,11).
m = (20-2) / (10-1) = 2.
m2 = -1/2 = slope of P.B. of PR.
Y = (-1/2)*5.5 + b = 11,
-2.75 + b = 11,
b = 11 + 2.75 = 13.75.
Eq2: Y = -X/2 + 13.75 = P.B. OF PR.
Substitute 13 for X:
Y = -13/2 + 13.75 = 7.25.
C(13,7.25).=Coordinates of circumcenter
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