The atomic mass of iron oxide is 160 atomic mass units. What is the atomic mass of iron if a molecule of iron oxide consists of tow atoms of iron and three atoms of oxgen?

let us assume that O is 16

then 3 O = 48
then I +48 = 160
I = 160-48

Damon,

Is the answer the same with 2 atoms of iron?
Thank you so much....

The atomic mass of iron oxide is 160 atomic mass units. What is the atomic mass of iron if a molecule of iron oxide consists of two atoms of iron and three atoms of oxgen?

Oh sorry

2 I = 160 - 48

That is 56 which is what you will find if you look up the atomic mass of iron using Google

To find the atomic mass of iron, we need to use the given information that a molecule of iron oxide consists of two atoms of iron and three atoms of oxygen, and the atomic mass of iron oxide is 160 atomic mass units.

First, let's calculate the total atomic mass of the three oxygen atoms in iron oxide. Since each atom of oxygen has an atomic mass of 16 atomic mass units, the total atomic mass of the three oxygen atoms is 3 * 16 = 48 atomic mass units.

Next, we can find the atomic mass of iron by subtracting the total atomic mass of the three oxygen atoms from the atomic mass of iron oxide.

Atomic mass of iron = Atomic mass of iron oxide - Total atomic mass of oxygen
Atomic mass of iron = 160 - 48
Atomic mass of iron = 112 atomic mass units

Therefore, the atomic mass of iron is 112 atomic mass units.