Saturday

February 28, 2015

February 28, 2015

Posted by **Juan** on Sunday, April 24, 2011 at 1:16pm.

- math -
**MathMate**, Sunday, April 24, 2011 at 3:06pmDistance, V, in inches travelled from rest under gravity

= (1/2)gt²

= (1/2)32'*12"/' t²

Since the hang time T includes upward and downward movements, T=2t, so equation above becomes

192(T/2)² = V

hence

V=48T²

Substitute V=35" to get

35=48T²

Solve to get

T=sqrt(35/48)=0.854 sec.

**Answer this Question**

**Related Questions**

Math - If a pro basketball player has a vertical leap of about 35 inches, what ...

ALGEBRA - If a pro basketball player has a vertical leap of about 35 inches what...

math-- algebra - If a pro basketball player has a vertical leap of about 25 ...

algebra - IF a pro basketball player has a vertical hang-time of about 35 inches...

algebra-is this right - A basketball player has a vertical leap of about 36 in. ...

Algebra - Hang time? If a basketball player has a vertical leap of about 30 ...

algebra - 1. If a pro basketball player has a vertical leap of about 20 inches, ...

algebra II - If a pro basketball player has a vertical leap of about 25 inches, ...

algebra - If a pro basketball player has a vertical leap of about 20in., what is...

Algebra - If a pro basketball player has a vertical leap of 25 inches, what is ...