Posted by Trista Nigh on Saturday, April 23, 2011 at 9:21pm.
..............HA + NaOH ==> NaA + H2O
..............x.....0........0.....0
add................30 mmols..........
change.......-30...-30.....+30.....+30
equil........x-30....0......+30....+30
pH = pKa + log (base)/(acid)
4.25 = 3.886 + log(30/(A)
Solve for A. I found 12.98; therefore, the value for x, the initial HA, is 12.98 + 30 = 42.98 mmoles or 0.04298 moles.
n = grams/molar mass. Solve for molar mass. You know g and n.
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