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April 1, 2015

April 1, 2015

Posted by **physicsclass** on Saturday, April 23, 2011 at 7:57pm.

a. Current of 4 A in 1 min

b. Current of 2 A in 0.5 min

c. Current of 8 A in 2 min

d. All are the same charge

I think the answer is C? Since the formula for finding current is 1 = C / s = 1 Ampere. So wouldn't I just have to multiply the current and minutes to get the net charge?

How long would it take for a net charge of 2.5 C to pass a location in a wire if it is to carry a steady current of 5 mA? I know in order to convert mA to amps, divide by 1000, so 5/1000=5x10^-3A. Now what do I do? I thought I'd have to switch the original formula around so I divide the net charge by the current to get the time?

- 2 more physics questions I need help on, please? -
**Damon**, Saturday, April 23, 2011 at 8:08pmcurrent in amps is coulombs of charge per second

I = Q/t

so

Q = I t

4*1 = 4

2*.5 = 1

8*2 = 16 coulombs

Q = i t

so

t = Q/i

t = 2.5 /5*10^-3 = (1/2) * 10^3

= 500 seconds

- 2 more physics questions I need help on, please? -
**Austin**, Tuesday, November 13, 2012 at 2:51pmThe answer is D

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