x² + 18x -4 = 0
Use Quadratic Eq and get:
X = 0.2195, and -18.22.
Or
(0.2195,0), (-188.22,0).
D answer is nt correct
To solve the quadratic equation x² + 18x - 4 = 0, you can use the quadratic formula:
x = (-b ± √(b² - 4ac)) / (2a)
In this equation, a, b, and c represent the coefficients of x², x, and the constant term, respectively.
For the given equation, the coefficients are:
a = 1
b = 18
c = -4
Plugging these values into the quadratic formula, we get:
x = (-18 ± √(18² - 4(1)(-4))) / (2(1))
Simplifying further:
x = (-18 ± √(324 + 16)) / 2
x = (-18 ± √340) / 2
x = (-18 ± √(4*85)) / 2
x = (-18 ± 2√85) / 2
Finally, we can simplify and solve for x:
x₁ = (-18 + 2√85) / 2
x₁ = -9 + √85
x₂ = (-18 - 2√85) / 2
x₂ = -9 - √85
So, the solutions to the equation x² + 18x - 4 = 0 are x = -9 + √85 and x = -9 - √85.