the graph of y=-(x^2/3)=2x=24 is a parabola.

1) is the parabola u-shaped or n-shaped. how can you tell this from the equation?

I THINK I GOT IT ITS NEGATIVE AS THE COEFFIENT IS -X^2 WHICH IS NEGATIVE. IS THIS RIGHT?

You're close.

If the leading coefficient (the coefficient of the x² term) of a parabola is negative, then the graph is n-shaped.
If the leading coefficient is positive, it is u-shaped.

To determine whether the parabola is u-shaped or n-shaped, we need to analyze the equation.

First, it seems that the given equation has a typographical error. It appears to be y = -x^(2/3) + 2x + 24 instead of y = -(x^2/3) = 2x = 24. I will assume this is the correct equation.

The given equation is in the form of a quadratic function, y = ax^2 + bx + c, where a, b, and c are constants. In this case, a = -1, b = 2, and c = 24.

Since the coefficient of x^2 is negative (-1), the parabola opens downwards, making it n-shaped. This is because a negative coefficient of x^2 causes the graph to be reflected vertically.

To determine this characteristic, you can look at the coefficient of x^2 in the equation. If it is positive, the parabola opens upwards (u-shaped). If it is negative, the parabola opens downwards (n-shaped).