The Kb for butylamine is 5.9x10^-4. What is the Ka for its corresponding conjugate acid, butylammonium?
I really need help with this. I have no idea what to do. All I know is the equation to fine "Ka."
You need to know just one formula to convert from Ka to Kb.
KaKb = Kw; therefore,
Ka for the salt = Kw/Kb for the base.
