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November 28, 2014

November 28, 2014

Posted by **niki** on Friday, April 22, 2011 at 7:25am.

- physics -
**drwls**, Friday, April 22, 2011 at 11:10amSince no heat is added, you must be increasing the temperature by isentropic compression. Negative work is done BY the gas.

For (a) Calculate the P dV integral using the fact that

Po*Vo^(5/3) = P*V^(5/3)

Work = integral P dV =

Po*Vo^(5/3)* integral of dV/V^(5/3)

More information is required about the initial conditions of the gas. Does it start out at S.T.P. ?

- physics -
**drwls**, Friday, April 22, 2011 at 12:51pm(b) Since this is an adiabatic process, the heat transferred in or out is zero. That is the definition of adiabatic.

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