Monday

March 30, 2015

March 30, 2015

Posted by **Amy** on Thursday, April 21, 2011 at 3:50pm.

- calculus -
**Mgraph**, Thursday, April 21, 2011 at 4:38pmSeparate the variables:

27sqrt(y)dy=2(x-3)sqrt(x^2-6x+23)dx

Let z=x^2-6x+23, then dz=(x^2-6x+23)'dx=

(2x-6)dx=2(x-3)dx

27sqrt(y)dy=sqrt(z)dz

Integrating both sides gives

18y*sqrt(y)=(2/3)*z*sqrt(z)+C

18y*sqrt(y)=(2/3)*(x^2-6x+23)*sqrt(x^2-6x+23)+C

**Answer this Question**

**Related Questions**

calculus - I posted this below, and no one answered. Please help with this very ...

calculus - Please help with this very complicated question! Using 3(x-3)(x^2-6x+...

Math - Calculus Question. - hey can someone explain to me the relationship ...

Calculus - Using 3(x-3)(x^2-6x+23)^1/2, as the chain rule differentiation of f(x...

calculus - how do not understand how to find a deriviative of this function?Do i...

Calculus - How do I use the chain rule to find the derivative of square root(1-x...

Calculus - Can anyone explain how to use the chain rule and power rule together ...

Algebra - I posted this earlier but it didn't get answered. So I'm posting it ...

Product Rule - Can someone please help me with this? f(x)=(x-2)^1/2 * (x^2-3)^3 ...

MoRe HeLp PlEaSe!! (calc) - Also can I get some help with this LONG, TIRESOME ...