Wednesday

August 20, 2014

August 20, 2014

Posted by **Amy** on Thursday, April 21, 2011 at 3:50pm.

- calculus -
**Mgraph**, Thursday, April 21, 2011 at 4:38pmSeparate the variables:

27sqrt(y)dy=2(x-3)sqrt(x^2-6x+23)dx

Let z=x^2-6x+23, then dz=(x^2-6x+23)'dx=

(2x-6)dx=2(x-3)dx

27sqrt(y)dy=sqrt(z)dz

Integrating both sides gives

18y*sqrt(y)=(2/3)*z*sqrt(z)+C

18y*sqrt(y)=(2/3)*(x^2-6x+23)*sqrt(x^2-6x+23)+C

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