Homework Help: physics

Posted by Allison on Thursday, April 21, 2011 at 5:30am.

The 4.00-kg block in the figure is attached to a vertical rod by means of two strings. When the system rotates about the axis of the rod, the strings are extended towards the rod and each have a length of 1.25. The length from the upper string and lower string on the rod is 2. So it forms a triangle with sides 2, 1.25, 1.25; with the block between the 1.25 sides. The tension in the upper string is 85.0 N . Tension of the lower cord is 36 N.

a) How many revolutions per minute does the system make?

b)Find the number of revolutions per minute at which the lower cord just goes slack.

physics - Jose, Wednesday, May 18, 2011 at 8:54pm
For part a)

T1 = Upper cord
T2 = Lower cord
theta = angle between vertical rod and upper cord = arcos(1/1.25)
R = radius of circular motion = sqrt((1.25^2) + 1^2)
M = mass of object

T1sin(theta)+T2sin(theta) = (MV^2)/R

Solve for V

Turn your V (should be in m/s) into revs/min.

rev = circumference = 2Rpi
m/s * 1 rev/(2Rpi)m * 60s/1min = rev/min

V in rev/min = (60V)/(2Rpi)

Haven't figured out part b) yet

Answer this Question

Related Questions

physics - A massless rod of length 1.00 m has a 2.00-kg mass attached to one end...
physics - A 4.00-kg object is attached to a vertical rod by two strings. The ...
Physics - a ball of mass m is attached by two strings to a vertical rod (lower ...
Physics - a ball of mass m is attached by two strings to a vertical rod (lower ...
Physics - a ball of mass m is attached by two strings to a vertical rod (lower ...
physics - a 1.29 kg ball is connected by means of two massless strings to a ...
science - A ball of mass m is attached by two strings to a vertical rod. as ...
physic - A 4 kg object is attached to a vertical rod by two strings, as in the ...
physics - A 4.00 kg mass and a 3.00 kg mass are attached to opposite ends of a ...
physics - A light rigid rod 1.00 m in length joins two particles, with masses 4....

For Further Reading

First Name:
School Subject:
Answer: