Posted by judith on Wednesday, April 20, 2011 at 8:07pm.
Let n = number of years required:
Compound interest:
3P=P(1.095)^n
Solve for n:
3=1.095^n
take log on both sides:
n log(1.095)=log(3)
n = log(3)/log(1.095)
Simple interest:
3P=P(1+0.095*n)
Solve for n:
n=(3-1)/0.095 = 2/0.095
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