Question

log (base 9) (x-2) + log (base 9) (x-2)=1

Solve algebraically.

Answer 1

2 log9 (x-2) = 1

log9 (x-2)^2 = 1
(x-2)^2 = 9^1 = 9

x^2 - 4x + 4 = 9

x^2 -4 x -5 = 0
(x-5)(x+1) = 0
x = 5 or x = -1