Posted by **Chuck** on Wednesday, April 20, 2011 at 11:06am.

Solve the following, then check your answer by graphing.

x^2+4y^2=25

y^2-x=1

- algebra -
**Henry**, Thursday, April 21, 2011 at 11:37pm
Eq1: X^2 + 4Y^2 = 25.

Eq2: Y^2 - X = 1.

Y^2 = X + 1.

In Eq1, substitute

- algebra -
**Henry**, Friday, April 22, 2011 at 12:06am
Eq1: X^2 + 4Y^2 = 25.

Eq2: Y^2 - X = 1.

Y^2 = X + 1.

In Eq1, substitute X+1 for Y^2:

X^2 + 4(X+1) = 25,

X^2 + 4X + 4 = 25,

(X+2)^2 = 25,

Take sqrt of both sides:

X+2 = +-5,

X = X = 5-2 = 3.

X = -5-2 = -7.

Solution set: (3,+-2), (-7,+-sqrt6i).

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