algebra
posted by Chuck on .
Solve the following, then check your answer by graphing.
x^2+4y^2=25
y^2x=1

Eq1: X^2 + 4Y^2 = 25.
Eq2: Y^2  X = 1.
Y^2 = X + 1.
In Eq1, substitute 
Eq1: X^2 + 4Y^2 = 25.
Eq2: Y^2  X = 1.
Y^2 = X + 1.
In Eq1, substitute X+1 for Y^2:
X^2 + 4(X+1) = 25,
X^2 + 4X + 4 = 25,
(X+2)^2 = 25,
Take sqrt of both sides:
X+2 = +5,
X = X = 52 = 3.
X = 52 = 7.
Solution set: (3,+2), (7,+sqrt6i).