If there is anything about log, it is logarithmic
So take the log of both sides,
log 300 = log 8y
Writing 300 as 3*100,
Using log(AB) = log A+log B,
log 3+log100=log 8+log y
Because log 100=2,
log 3+2=log 8+log y
Rearrange: log 8-log 3=log y-2
By log(A/B)=log A-log B,
log (8/3)=log y-2
Write 8y = 300 in its equivalent logarithmic form
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