Wednesday

April 1, 2015

April 1, 2015

Posted by **iqra** on Wednesday, April 20, 2011 at 8:04am.

- math:Calculus -
**Mgraph**, Wednesday, April 20, 2011 at 10:57amFind the point of intersection of the graph of the function and the x-axis:

X^2+6X-8=0

X1=-3-sqrt(17), X2=-3+sqrt(17)

CHECK FUNCTION!

**Answer this Question**

**Related Questions**

Calculus - Approximate the area under the curve on the given interval using n ...

Calculus-Aproximate Areas - Estimate the area under the graph of f(x)=sin(pix) ...

Calculus-Aproximate Areas - Estimate the area under the graph of f(x)=sin(pix) ...

geometry - One endpoint and the midpoint of a segment are given. Find the ...

Calculus urgent - For the intergral of -(x^2)/3 +6 interval [0,3] Rewrite it as ...

Calculus-Math - The endpoints of a movable rod of length 1 m have coordinates (x...

Calculus - 1. Find the area of the region bounded by the curves and lines y=e^x ...

trig - Find the other endpoint of the line segment with the given endpoint and ...

calculus - For the intergral of -(x^2)/3 +6 interval [0,3] Rewrite it as a ...

Math, please check work - find the other endpoint of a line segment with the ...