Posted by sam on .
Find the area of the region enclosed between y=2sin(x and y=3cos(x) from x=0 to x=0.4pi
Hint: Notice that this region consists of two parts.
Notice: I'm getting 1.73762 but apparently that is wrong.
Calc 2: Area under the curve -
Find x where 2sin(x)=3cos(x) (div by cos)
Area(from x=0 to x=56.31)=
Area(from x=56.31 to x=72)=
The total area=1.60555+0.13435=1.7399