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September 2, 2014

September 2, 2014

Posted by **sam** on Wednesday, April 20, 2011 at 3:32am.

Hint: Notice that this region consists of two parts.

Notice: I'm getting 1.73762 but apparently that is wrong.

- Calc 2: Area under the curve -
**Mgraph**, Wednesday, April 20, 2011 at 7:20amFind x where 2sin(x)=3cos(x) (div by cos)

2tan(x)=3

tan(x)=1.5

x=56.31degr

Area(from x=0 to x=56.31)=

(3sin(56.31)+2cos(56.31)-(3sin(0)+2cos(0))

=3.60555-2=1.60555

Area(from x=56.31 to x=72)=

(-2cos(72)-3sin(72))-(-2cos(56.31)-3sin(56.31))=-3.47120-(-3.60555)=0.13435

The total area=1.60555+0.13435=1.7399

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