Find the equation of the line tangent to the graph of y=4 e^x at x=2.
I always get confused with tangent lines
I worked this out to be
4e^x(x-2)+4e^2 but the program i have to submit it to says its wrong.
Calculus - Mgraph, Tuesday, April 19, 2011 at 11:59pm
The equation of the tangent to the graph
y=f(x) at x=a: