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November 25, 2014

November 25, 2014

Posted by **Alex** on Tuesday, April 19, 2011 at 11:23pm.

I always get confused with tangent lines

I worked this out to be

4e^x(x-2)+4e^2 but the program i have to submit it to says its wrong.

- Calculus -
**Mgraph**, Tuesday, April 19, 2011 at 11:59pmThe equation of the tangent to the graph

y=f(x) at x=a:

y=f(a)+f'(a)(x-a)

(4e^x)'=4e^x

y=4e^2+4e^2(x-2)

y=4e^2*x-4e^2

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