Post a New Question
posted by Marissa on Tuesday, April 19, 2011 at 10:58pm.
Let f be a function such that f(-1)=3 and f'(-1)=6 let h(x)=x^5f(x) evaluate h'(x) at x=-1
h'(x)=5*x^4*f(x)+x^5*f'(x) h'(-1)=5*(-1)^4*f(-1)+(-1)^5*f'(-1)= 5*1*3+(-1)*6=15-6=9
More Related Questions