calculate the mass of sodium nitrate in grams in a 150 ml solution of a 5.00 M solution of sodium nitrate
To calculate the mass of sodium nitrate, we need to know the molarity of the solution and the volume of the solution. Given that the molarity is 5.00 M and the volume is 150 mL (or 0.150 L), we can follow these steps:
Step 1: Convert the volume from mL to L.
150 mL * (1 L / 1000 mL) = 0.150 L
Step 2: Use the equation Molarity (M) = Moles (n) / Volume (V) to calculate the number of moles.
M = n / V
5.00 M = n / 0.150 L
Rearranging the equation to solve for moles:
n = M * V
n = 5.00 M * 0.150 L
n = 0.750 moles
Step 3: Calculate the molar mass of sodium nitrate (NaNO3).
The molar mass of sodium (Na) is 22.99 g/mol, nitrogen (N) is 14.01 g/mol, and oxygen (O) is 16.00 g/mol.
Molar mass of NaNO3 = (22.99 g/mol) + (14.01 g/mol) + (3 * 16.00 g/mol)
Molar mass of NaNO3 = 85.00 g/mol
Step 4: Use the equation Moles (n) = Mass (m) / Molar mass (M) to calculate the mass of sodium nitrate.
0.750 moles = m / 85.00 g/mol
Rearranging the equation to solve for mass:
m = n * M
m = 0.750 moles * 85.00 g/mol
m = 63.75 grams
Therefore, the mass of sodium nitrate in the 150 mL solution is 63.75 grams.