If the equation is :
Cd2+(aq) + Cl-(aq) ¡ê CdCl+
What would happen when Na+ is added would it shift to the right or will there be no change/effect to the system?
adding more positive ions. It shifts to the left,trying to remove them.
To determine what would happen when Na+ is added to the system, we need to consider the solubility of the compounds involved and the effect of the common ion on equilibrium.
In the given equation:
Cd2+(aq) + Cl-(aq) ⇌ CdCl+
The formation of CdCl+ involves the combination of the Cd2+ cation and Cl- anion. It is important to note that CdCl+ is not a stable compound in aqueous solution, so it further reacts with water to form CdOH+ and HCl.
Now, let's consider the effect of adding Na+ ions to the system. Na+ is a common ion with Cl- because both ions are present in the compound NaCl. The presence of a common ion can affect the solubility and the equilibrium position of the reaction.
When Na+ ions are added, they will compete with the Cd2+ ions for the available Cl- ions in the solution. This increased concentration of Cl- ions due to the addition of Na+ ions may decrease the solubility of the CdCl+ compound, resulting in a shift in the equilibrium to the left.
Therefore, when Na+ is added, the equilibrium will shift towards the formation of more Cd2+ and Cl- ions, leading to a decrease in the concentration of CdCl+ in the solution.
So, in summary, the addition of Na+ ions would shift the equilibrium towards the left, resulting in a decrease in the formation of CdCl+ in the solution.