In a rack of 15 billiard balls and one ball is selected at random what are the odds in favor it being a ball other than the 8 ball.
I thought it would be 1/15 but I am not sure.
Anyone help me on this?
it is 14/15. THere are 15 total balls. 14 are normal, 1 is the eight ball. There is a 14/15 chance u get a norm one, and 1/15 you get the eight ball
To determine the odds in favor of selecting a ball other than the 8 ball, we first need to find the total number of possible outcomes and the number of favorable outcomes.
Total number of outcomes: There are 15 billiard balls in the rack.
Number of favorable outcomes: We want to select any ball other than the 8 ball, so there are 15 - 1 = 14 favorable outcomes.
Therefore, the odds in favor of selecting a ball other than the 8 ball can be expressed as the ratio of the number of favorable outcomes to the total number of outcomes, which is:
Odds in favor = Number of favorable outcomes / Total number of outcomes
= 14 / 15
Simplifying, we find that the odds in favor of selecting a ball other than the 8 ball are 14/15.
To determine the odds in favor of selecting a ball other than the 8 ball, we need to know the total number of balls and the number of balls that are not the 8 ball in the rack.
In this case, the rack consists of 15 billiard balls. Since only one of these balls is the 8 ball, there are 15 - 1 = 14 balls in the rack that are not the 8 ball.
Therefore, the odds in favor of selecting a ball other than the 8 ball would be 14 out of the total 15 balls in the rack.
So, the correct probability is 14/15, not 1/15.