Wednesday

April 16, 2014

April 16, 2014

Posted by **Chiara** on Tuesday, April 19, 2011 at 4:02pm.

integral (x^3)/(sqrt(25+9x^2)) dx

/ l

/ l

/ l

/ l

/ l

/ l

/ l

/ l

/ l side A

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/ l

---------

side B

*** sorry hard to draw on the computer

side a=3x

side b=?

side c=?

3x/5=?

(3/5) dx=?

(sqrt(25+9x^2))/(5)=?

- calculus -
**bobpursley**, Tuesday, April 19, 2011 at 4:07pmwell, if side c is the hypotenuse, then

side c= sqrt(25+9x^2)

side a=3x

side b=5

3x/5 = tan C

3/5 dx= d(tanC)

Sqrt(25+9x^2)/5=secC

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