Posted by **Janet** on Monday, April 18, 2011 at 9:36pm.

The position in meters of a particle is given by f(t)= 14t-3t^2, where t is measured in seconds.

a) Evaluate f'(2) and interpret the results.

This is how I solved this. f'(t)=14-6t= 2(7-3t)

f'(2)=2(7-3(2))= 2 This means the velocity of the particle is 2 m/s when t=2.

b) On what intervals is the particle speeding up?

I don't know how to do this part.

Please help

## Answer This Question

## Related Questions

- calculus - a particle moves along a number line measured in cm so that its ...
- Calculus - The position of a function of a moving particle is s(t)=5+4t-t^2 for ...
- calc help - the position function of a particle is given by s=t^3–4t^2–7t t>=...
- Calculus(math) - A particle is moving on a straight line in such a way that its ...
- Calculus - The position of a particle moving on a horizontal line is given by s(...
- MATH - The position function of a particle is given by s(t) = t^{3}-3t^{2}-7t, t...
- Calculus - A particle moves along a horizontal line so that at any time t its ...
- calculus - velocity of a particle- the displacement s (in meters) of a particle...
- Calculus - Sorry this is really long. Just wondering how I would do each of ...
- Calculus (Derivatives) - Two particles are moving in straight lines. The ...

More Related Questions