. Find the volume of the sphere with a radius of 9. Use ð = 3.14 and round your answer to the nearest tenth.

4. Find the volume of an ellipsoid with a semi-major axis of length 10 and the first semi-minor axis has length of 6 while the second semi-minor axis has length of 4. Use ð = 3.14 and round your answer to the nearest tenth.

5. Find the volume of a cylinder whose base has a diameter of 10 and whose height is 12. Use ð = 3.14 and round answer to the nearest tenth.

6. Find the volume of a cone whose base's radius is 4 and whose height is 13. Use ð = 3.14 and round to the nearest tenth.

7. Given the volume of a cube of 1,953.125 cm3, find the length of the sides. Round your answer to the nearest tenth.

8. Find the volume of a cube whose sides each measure 6.2. Round answer to the nearest tenth.

Find the volume. If necessary, round to the nearest hundredth. (Assume a = 2 ft, b = 3 ft, and c = 9 ft.)

To find the volume of a sphere with a given radius, you can use the formula V = (4/3)πr^3, where V is the volume and r is the radius.

For the first question, the radius of the sphere is 9. Using the given value of π as 3.14, we can substitute these values into the formula to find the volume.

V = (4/3) * 3.14 * 9^3
V ≈ 4.187 * 729
V ≈ 3053.628
Rounded to the nearest tenth, the volume of the sphere is approximately 3053.6 cubic units.

To find the volume of an ellipsoid, you can use the formula V = (4/3)πabc, where V is the volume, a is the length of the semi-major axis, b is the length of the first semi-minor axis, and c is the length of the second semi-minor axis.

For the second question, the lengths of the axes are as follows:
a = 10
b = 6
c = 4

Substituting these values into the volume formula, we get:

V = (4/3) * 3.14 * 10 * 6 * 4
V ≈ 4.188 * 240
V ≈ 1005.312

Rounded to the nearest tenth, the volume of the ellipsoid is approximately 1005.3 cubic units.

To find the volume of a cylinder, you can use the formula V = πr^2h, where V is the volume, r is the radius of the base, and h is the height.

For the third question, the diameter of the base is given as 10, so the radius is half of that, which is 5. The height of the cylinder is given as 12.

Substituting these values into the formula, we get:

V = 3.14 * 5^2 * 12
V ≈ 3.14 * 25 * 12
V ≈ 942

Rounded to the nearest tenth, the volume of the cylinder is approximately 942 cubic units.

To find the volume of a cone, you can use the formula V = (1/3)πr^2h, where V is the volume, r is the radius of the base, and h is the height.

For the fourth question, the radius of the base is given as 4, and the height is given as 13.

Substituting these values into the formula, we get:

V = (1/3) * 3.14 * 4^2 * 13
V ≈ (1/3) * 3.14 * 16 * 13
V ≈ 215.333

Rounded to the nearest tenth, the volume of the cone is approximately 215.3 cubic units.

To find the length of the sides of a cube, given the volume, you can use the formula V = s^3, where V is the volume and s is the length of each side.

For the fifth question, the volume is given as 1,953.125 cm^3.

Substituting this value into the formula, we get:

1953.125 = s^3

To find the length of each side, we need to take the cube root of the volume. Using a calculator, we get:

s ≈ 12.5

Rounded to the nearest tenth, the length of each side of the cube is approximately 12.5 cm.

To find the volume of a cube, you can use the formula V = s^3, where V is the volume and s is the length of each side.

For the sixth question, the length of each side is given as 6.2.

Substituting this value into the formula, we get:

V = 6.2^3
V ≈ 238.328

Rounded to the nearest tenth, the volume of the cube is approximately 238.3 cubic units.