Posted by Jane on Monday, April 18, 2011 at 5:07pm.
find the point on the line 6x+7y5=0 closest to (2,2)

calculus  Jenn, Monday, April 18, 2011 at 5:22pm
6x+7y5=0
+5 +5
6x+7y=5
6x 6x
7y=56x
/7 /7
y=(56x)/7
Posted by Jane on Monday, April 18, 2011 at 5:07pm.
find the point on the line 6x+7y5=0 closest to (2,2)
6x+7y5=0
+5 +5
6x+7y=5
6x 6x
7y=56x
/7 /7
y=(56x)/7