Posted by Declan on Monday, April 18, 2011 at 4:27pm.
As I understand the picture,
mg/tension = cos60 solve for tension.
Now, on the rockface putting a force on the climber. It depends on where the force is. Is the force the climber normal to the rockface, or at some angle?
assuming normal, then a sketch on the rope wall face triangle, shows F/Tension=sin30, solve for F. The rockface has an equal and opposite force.
I hope I understood the picture.
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