Posted by Bob on Monday, April 18, 2011 at 4:20pm.
Don't we need to know how much solution we are to prepare? I'll assume we are to use 1 kg water.
1.00 m CaCl2 = 110.983 g CaCl2/kg water.
What's the density of the solution. I will assume 1.00 g/mL which probably is not a valid assumption.
81,300 J = 1,000g x 4.184 J/C*g x (Tfinal-27)
Solve for Tfinal.
Check my thinking.
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