Would you like to post your answer if you just wanted to check?
y=... or r=...?
It would be in the form:
where f and g are functions of θ.
Read the terms of your problem!
x^2 = y
x^2 = y
I am sorry, it is r = 5tan(theta)sec(theta)
Mggraph: but (r*cos(theta))^2 is not x^2, is it? I thought rcos(theta) = x^2
This is what I got:
1 = 5y/[(x^2)(square root of(x^2 + y^2))]
Then all right sides multiply by 5:
Aha I got it! Thanks so much! :)
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